If two parents who are both of normal phenotype (i.e. not albino) were to have an albino child, the genotype of the two parents would be heterozygous for the alleles that determine albinism. This means that the parents each possess one allele that codes for albinism and one allele that codes for normal pigmentation, but they do not express the albinism allele in their phenotype. The inheritance of albinism is an autosomal recessive trait, so the child would have to inherit two albinism alleles, one from each parent, in order to be albino.
The genotype of the albino child would be homozygous for albinism, meaning they possess two albinism alleles. This is because in order for the child to be albino, they must possess two albinism alleles and no normal pigmentation alleles. Since the parents are heterozygous, they each have one albinism allele and one normal pigmentation allele, and when their alleles combine, the likelihood of the child inheriting two albinism alleles is 25%. Therefore, it is possible for two normal phenotype parents to have an albino child, as long as one of the parents carries the albinism allele and the other parent also carries the same allele.